PA-11 House election: Lloyd Smucker vote percent: Will Lloyd Smucker receive at least 68% of the popular vote in the 2026 PA-11 House election?

If the certified percentage of the popular vote received by Lloyd Smucker in the 2026 PA-11 House election is 68% to 100%, inclusive of both endpoints, then the market resolves to Yes. The percentage is calculated as (total votes received by Lloyd Smucker ÷ total valid votes cast) × 100, rounded to two decimal places. Except as provided in the Contract, resolution is based on certified/official results only, not preliminary results. Write-in votes are included if they appear in certified results. Invalid, spoiled, or rejected ballots are excluded from both numerator and denominator.